Question

A person moves with a constant speed of 2 m/s
due north and covers a distance of 8 m and then
covers a distance of 6 m due east with a constant
speed of 3 m/s. His magnitude of average velocity
for his entire journey is​

Answer 1

Answer:

10/6seconds or 1.67second

Explanation:

When the person moves towards north with speed of 2m/s,time taken=8÷2=4seconds

when he moves towards east time taken=6÷3=2seconds

Now his total displacement =10m

so,average velocity=total displacement

_____________________

total time taken

=10/4+2

=10/6seconds

Answer 2

Answer:

u = 2m/s

s = 8m

t = S/ U (as, U = S/T )

t= 8/2 = 4s

then,

U = 3m/s

S = 6m

T = s/u (as, u= s/t)

T=6/3 = 2s

average velocity =

$\frac{U - u}{T-t} \\ = \frac{6 - 8}{3 - 4} \\ = \frac{ - 2}{ - 1} \\ = 2m {s}^{ - 1}$

so, the average velocity is 2m/s .