Question

A person moving in a car with a velocity of 36Km/h towards a large wall blows the horn, if he hears the echo after 4 sec, then find the distance of wall from him when he blows the horn.
(velocity of sound =330ms^-{1}

Answer 1

Explanation:

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Answer 2

$d=680\ m$ is the distance of wall from the car when the horn was blown.

Explanation:

Given:

• velocity of car, $v=36\ km.hr^{-1}=10\ m.s^{-1}$

• time after which the echo is heard, $t=4\ s$

• velocity of sound, $s=330\ m.s^{-1}$

Now the distance covered by the car in 4 seconds:

$d_c=v.t$

$d_c=10\times 4$

$d_c=40\ m$

As the distance covered by the sound in 4 seconds will be the distance covered by the car in 4 seconds + twice the distance between the wall and the car.

Hence the distance between the wall and the car:

$d_s=\frac{s.t-40}{2}$

$d_s=\frac{330\times 4-40}{2}$

$d_s=640\ m$

Therefore the distance of wall from the car when the horn was blown:

$d=d_s+d_c$

$d=640+40$

$d=680\ m$

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TOPIC: DISTANCE SPEED TIME

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