Question

A person nearest distant of vision is 1m . What would be the optical power of lens used

Answer 1

Answer:

For a normal eye, the near point is at a distance of 25 cm. The farthest point up to which an eye can see clearly is called its far point. For a normal eye, the far point is at infinity.

Answer 2

it is given that the near point of defective eye is 1 m and that of a normal eye is 25 cm. Hence u = - 25 cm.