Question

a person needs a lens of power +2.5 diopter for correcting his vision. name the defect of vision he is suffering from? which type

of lens will he be using for correcting the defect also find the focal length of len

Answer 1

Convex lens
Short Sightedness
Power=1/focal length=1/2.5=0.4(Answer)

Answer 2

Converging lens - Convex lens is used and the person suffer from hypermypoia .

Power = 1 ÷ f

1÷ 2.5

100÷ 25

40 cm

Hope it will help you !!!