a person observed the angle of elevation of the top of a tower is 30 degree he was 50 metre towards the foot of the tower along level ground and found the angle of elevation of the top of the tower is 60 degree find the height of the tower
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Answer:
25root3
Step-by-step explanation:
firstly let initially man was standing at BD = x distance from tower
at that instant it is given that angle of elevation angle ABC = 30
now he moved 50 m towards tower ie BC = 50m
now BD = x BC= 50 so
CD = 50-x
also given that when man moved 50m towards tower angle of elevation ACD became 60
for solving we should know value of tan30 =1/root3 and tan60 =root3
also let height of tower = h
and in any triangle tan theta = perpendicular/base
rest u can see my attachment to see answer
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