Question

A person observed the angle of elevation of the top of a tower as 30 degree. He walked 50m towards the foot of the tower along the level ground and found the angle of elevation of the top of the tower as 60 degree. Find the height of the tower.

Answer 1

ok check the answer dude

Answer 2

We will assume h be the height of the building.

ΔABC tan 60° = AB/BC

√3 = h/x

x = h/√3

And in the Right Angle ABD,

tan 30° = AB/BD

= 1/√3 = h/ x + 50

= h/√3 + 50 = √3h

h = 25√3m

If there is any confusion please leave a comment below.