A person observes the angle of elevation of a building as 30°. The persons proceeds towards the building
with a speed of 25(03-1) m/h. After two hours, he observes the angle of elevation as 45° The height of
the building (in metres)is
1) 50(V3 - 1) 2) 50(V3+ 1)
3) 50
4) 100
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Answer:
Step-by-step explanation:
We will assume h be the height of the building.
ΔABC tan 60° = AB/BC
√3 = h/x
x = h/√3
And in the Right Angle ABD,
tan 30° = AB/BD
= 1/√3 = h/ x + 50
= h/√3 + 50 = √3h
h = 25√3m
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