A person of 55 kg is holding a weight of 20 kg on his head. Calculate the work that is done against the gravitational force by it if it is to distance 20 meters (i) on a horizontal road, (ii) on such an inclined plane that has a horizontal tilt from 8 = sin '(1/5). Answer: (i) Zero, (ii) 3000 Joules. .
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W = f.s.costhita
W = mg . s cos this
m = 55+20kg
= 75kg
s = 20m
g = 9.8
So , W = 75×9.8 × 20 cos90
work done = 0
W = mg . s cos this
m = 55+20kg
= 75kg
s = 20m
g = 9.8
So , W = 75×9.8 × 20 cos90
work done = 0
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