Question

A person of height 1.65 m standing on a cliff of height 20 m above the water level on seashore can sight a ship at what distance?

Answer 1

Answer:

$\sqrt[2]{21.65^2+x^2}$ meters

Step-by-step explanation:

The distance between the eye level , sea level and ship form a right triangle.

We know that the height is

$(20+1.65)=21.65m$

Assume that the distance between a ship and the seashore is $x$ m.

Then the distance between the person and the ship is the hypotenuse of the triangle and can be found as;

$c=\sqrt[2]{a^2+b^2}$

a= 21.65m

b= x m

therefore;

$c=\sqrt[2]{21.65^2+x^2}$