Question

A person of mass 30 kg pushes another person of mass 40Kg due to which he first man starts moning with an acceleration of 2m/s. The acceleration of the second person at that instant is?
a) 2m/s^2
b) 3/2 m/s^2
c) 2/3m/s^2
d) 4/3m/s^2​

Answer 1

Answer:

We know from principle of momentum conservation , that ,

mv = m'v'

also , v = at and v' = a't

as initial velocities are 0.

substituting this ,

m.a.t = m'.a'.t

Hence ,

m.a = m'.a'

30×2 = 40 × a'

a' = 3/2 m/s^2

Hence option B is correct.