Question

a person of mass 40 kg is running with velocity 2m s changes to 6m/s in time interval 60 s . find initial k.e
​

Answer 1

Answer:

k = 80 joules

Explanation:

initial kinetic energy,

$k = \frac{1}{2} m {u}^{2}$

$k = \frac{1}{2} \times 40 \times {2}^{2}$

$k = 20 \times 4$

$k = 80 \: joules$

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