Physics, asked by srilatha2353, 5 months ago

a person of mass 40 kg is running with velocity 2m s changes to 6m/s in time interval 60 s . find initial k.e

Answers

Answered by Ayodhyavasi

Answer:

k = 80 joules

Explanation:

initial kinetic energy,

$k = \frac{1}{2} m {u}^{2}$

$k = \frac{1}{2} \times 40 \times {2}^{2}$

$k = 20 \times 4$

$k = 80 \: joules$

Hello dear my self Ravi Gupta from Ayodhya Uttar Pradesh

Hello dear my self Ravi Gupta from Ayodhya Uttar PradeshFor free PDF eBook you can subscribe our official YouTube channel

Hello dear my self Ravi Gupta from Ayodhya Uttar PradeshFor free PDF eBook you can subscribe our official YouTube channelhttps://www.youtube.com/channel/UCKAGyIO1nKysmccL9_apamw

Hello dear my self Ravi Gupta from Ayodhya Uttar PradeshFor free PDF eBook you can subscribe our official YouTube channelhttps://www.youtube.com/channel/UCKAGyIO1nKysmccL9_apamwmy email address - [email protected] my whatsapp number - 6388044617

Previous Question

Next Question

a person of mass 40 kg is running with velocity 2m s changes to 6m/s in time interval 60 s . find initial k.e​

Answers

a person of mass 40 kg is running with velocity 2m s changes to 6m/s in time interval 60 s . find initial k.e