a person of mass 50kg climbs a tower of height 72 meters. calculate the work done. (g=9.8m/s2)solve this question
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Answered by
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work done W=F.S=FScos(angle between force and displacement)
here force acting is weight that is mg
and displacement is height h
so w=mghcos(180)=-mgh=-50*9.8*72=35280joules
i hope it helps u
here force acting is weight that is mg
and displacement is height h
so w=mghcos(180)=-mgh=-50*9.8*72=35280joules
i hope it helps u
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Answered by
82
Answer:
Explanation:
Given :-
Mass of the person, m = 50 kg
Height of the person, h = 72 m
To Calculate:-
Work Done.
Formula to be used :-
Work done = mgh
Solution :-
While climbing the tower, work done is against the gravity.
Thus, work done equals to the potential energy.
Work done = mgh
Work done = (50 × 9.8 × 72) J
Work done = 35280 J.
Hence, the work done is 35280 J.
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