Question

A person of mass 50kg climbs a tower of height 72m calculate work done

Answer 1

Answer:

Work done by a person of 50 kg climbs a tower of height 72m is 36,000 Joule.

Explanation:

F = mg

F = 50 × 10 N

F = 500 N

W = FS

W = 500 × 72 Joule

W = 36000 Joule

Here,

F is the force.

m is the mass of body.

g is the acceleration due to gravity.

value of g is 10m/s^2.

W is the work done.

S is the displacement i.e., height of the tower.

Hence,.

Work done by a person of 50 kg climbs a tower of height 72m is 36,000 Joule.

Answer 2

Answer:

35280J

Explanation:

given ;

m=50kg

s=72m

g=9.8m$s^{2}$

w=f*s

f=m*g

f=50*9.8=490N

w=490*72=35280

w =35280J