A person of mass 60kg is inside a lift of mass 940kg and presses the button on control panel . Then lift starts moving upwards with an acceleration 1.0m/s*2 ,the tension in the supporting cable is :
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let the mass of man be m1 = 60 kg
mass of the lift be m2 = 940 kg
total mass M = m1+m2= 60+940= 1000 Kg
acceleration due to gravity = 9.8 m/s^2
acceleration of lift = - 1 m/s^2
T - mg = ma
T= ma + mg
T= m(a+g)
T= 1000(10.8)
T= 10800N
mass of the lift be m2 = 940 kg
total mass M = m1+m2= 60+940= 1000 Kg
acceleration due to gravity = 9.8 m/s^2
acceleration of lift = - 1 m/s^2
T - mg = ma
T= ma + mg
T= m(a+g)
T= 1000(10.8)
T= 10800N
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16
Answer:
The mass of a person is given as 60 kg who is "inside a lift" of mass 940 kg, starts moving upwards then the tension in the supported cable is the force due to gravity as well as acceleration, which can be calculated as follows -
Given, the mass of person = 60 kg
Mass of lift = 940 kg
Total mass = mass of lift + mass of person
Total mass = 940 + 60 = 1000 kg
Now, to have acceleration, the tension created in the supported cable must be equal to the force due to gravity as well as acceleration.
T = mg + ma
T = 1000(10+1)
T = 11000 N
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