Question

A person of mass M is, sitting on a swing of length L and swinging with an angular amplitude θ₀. If the person stands up when the swing passes through its lowest point, the work done by him, assuming that his centre of mass moves by a distance l ( l < < L), is close to :
(A) Mgl (1 + θ₀²) (B) Mgl (1 - θ₀²) (C) Mgl
(D) Mgl [(1+(θ₀²/2)]

Answer 1

Answer:

Work done against the gravity is Mgl

Explanation:

As we know that here angular momentum of the person will remain conserved

so here we will have

Here we can say that Centre of mass of the man moves upwards against the gravitational force

so work is done against gravity

So we will have

$W = F.d$

here we have

F = Mg

$W = Mgl$

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Topic : Work done against gravity

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