Question

A person of mass(m) is standing in a lift find his apparent weight when the lift is:Accelerating upward and downward with uniform acceleration, and during free fall

Answer 1

when the lift is going up
r > mg (Taking r as the apprent force)
That means that the weight of the man will increase
When coming down
r< mg
That means the weight of the man will be less than his original weight.
during free fall
a = g
since
r= mg (1-a/g)
=0 (since a=g)
This is the case of weightlessness.

Answer 2

See in this attachment....