A person of mass M kg is standing in a lift. If the lift moves vertically upwards
according to given v~t graph, then find out the weight of man at the following instants:
(Take g = 10 m/s)
(a) t= 1 second, (b) t = 8 seconds, (c)t = 12 seconds.
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Answer:
in case the information given is not enough to give the numerical value as there is no information of lift acceleration
Explanation: but
but it as the lift is going upward or if by inconstant acceleration then the given persons weight will increase .,if the acceleration of lift is constant then there will be no change in weight .thankyou!
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