Question

A person of mass M kg is standing on a lift. If the lift moves
vertically upwards according to given v-t graph then find out
vms) →
the weight of man at the following instants : (g = 10 m/s9
.
(i) t = 1 second
8
10 12 14 t(s)
(ii) t = 8 seconds
(iii) t = 12 seconds​

Answer 1

Explanation:

As lift moves up gravity is negative

weight of man =mg

N=mg

ma =mg