A person on a morning walk completes one round
around a circular park of diameter 500 m,
in 1 minute. What will be the distance covered and
the displacement at the end of 5 minutes 30 s?
Answers
ANSWER :-
distance:-- 2750m
distance:-- 2750mdisplacement:--. 500m
Step-by-step explanation:
Given that,
Diameter d = 500 m
Time t = 1 minute
A person on a morning walk completes one round around a circular park of diameter 500 m, in 1 minute.
So, The distance in 5 minute 30 sec will be
d = \pi rd=πr
d = \pi 500\times5+\pi 250md=π500×5+π250m
d = 2750\pid=2750m
A person cover one round of the circular park in 1 minute, that means after 1 minute the person come back to his initial position.
Therefore, The person covers 5 round in 5 minute so,
The displacement will be zero in 5 minute.
Now, the displacement will be in left 30 sec.
D = d_{f}-d_{i}D=d
f
−d
i
D = 500-0D=500−0
D = 500\ mD=500 m
Hence, The distance and the displacement will be 2750 m and 500 m.
Answer:
d=500 m
(2πr)
circumference =2π(
2
500
)
speed =500π
min
m
distance =500π
min
m
×5.5 min
=2750π m
=8635 m
Displacement
500π is one round
2750π is →?
500π
2750π
=5.5 rounds
displacement = length of diameter
=500 m.