Physics, asked by randeepsinghRISHI, 10 months ago

A person on a morning walk completes one round
around a circular park of diameter 500 m,
in 1 minute. What will be the distance covered and
the displacement at the end of 5 minutes 30 s?​

Answers

Answered by aramaswamy51
1

ANSWER :-

distance:-- 2750m

distance:-- 2750mdisplacement:--. 500m

Step-by-step explanation:

Given that,

Diameter d = 500 m

Time t = 1 minute

A person on a morning walk completes one round around a circular park of diameter 500 m, in 1 minute.

So, The distance in 5 minute 30 sec will be

d = \pi rd=πr

d = \pi 500\times5+\pi 250md=π500×5+π250m

d = 2750\pid=2750m

A person cover one round of the circular park in 1 minute, that means after 1 minute the person come back to his initial position.

Therefore, The person covers 5 round in 5 minute so,

The displacement will be zero in 5 minute.

Now, the displacement will be in left 30 sec.

D = d_{f}-d_{i}D=d

f

−d

i

D = 500-0D=500−0

D = 500\ mD=500 m

Hence, The distance and the displacement will be 2750 m and 500 m.

Answered by helyndhruvi
0

Answer:

d=500 m

(2πr)

circumference =2π(

2

500

)

speed =500π

min

m

distance =500π

min

m

×5.5 min

=2750π m

=8635 m

Displacement

500π is one round

2750π is →?

500π

2750π

=5.5 rounds

displacement = length of diameter

=500 m.

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