A person on tour has Rs 360 for his expense. If he extends his tour for 6 days, he has to cut down his daily expenses by Rs 3.Find the original duration of the tour.
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Let the original duration of the tour be x days.
Total expenditure on tour =Rs.360
Expenditure per day =Rs.x360
Duration of the extended tour =(x+4) days
Expenditure per day according to new schedule =Rs.x+4360
It is given that the daily expenses are cut down by Rs. 3
∴x360−x+4360=3
⇒x(x+4)360(x+4)−360x=3⇒x(x+4)360x+1440−360x=3
⇒x2+4x1440=3⇒x2+4x=480⇒x2+4x−480=0
⇒x2+24x−20x−480=0
⇒x(x+24)−20(x+24)⇒(x−20)(x+24)=0
⇒x−20=0orx+24=0⇒x=20,x=
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