A person on tour has RS. 4200 for his expenses. If he extends his tour for 3 days; he has to cut down his daily expenses by RS 70. Find the original duration of the tour. this question is biting me for a long time. plz help. I will rate :)
Answers
Answered by
296
Let the original duration of tour be x days
Amount with the person is Rs 4200
Daily expenses = Rs (4200/x)
Given tour extended for 3 more days
Hence total number of days = (x + 3) days
Daily expenses = Rs [4200/(x + 3)]
By the given problem, we have
(x + 15)(x – 12) = 0
Hence x = 12 as x cannot be negative
Thus the original duration of tour is 12 days.
Amount with the person is Rs 4200
Daily expenses = Rs (4200/x)
Given tour extended for 3 more days
Hence total number of days = (x + 3) days
Daily expenses = Rs [4200/(x + 3)]
By the given problem, we have
(x + 15)(x – 12) = 0
Hence x = 12 as x cannot be negative
Thus the original duration of tour is 12 days.
shailyyadav171:
after (by the given problem, we have) =4200/x-4200/x+3 =70 4200(1/x-1/x+3)=70 60[(x+3-x)/x(x+3)]=1 180=x*x+3x x*x+3x-180=0 x*x+15x-12x-180=0 x(x+15)-12(x+15)=0
plz mark as brailiest
Answered by
115
Answer:
Step-by-step explanation:
Solution :-
Let the original duration of the tour be x days.
Then,
According to the Question,
⇒ 4200/x - 4200/(x + 3) = 70
⇒ 4200[1/x - 1/(x - 3)] = 70
⇒ (x + 3) - x/x(x + 3) = 70/4200
⇒ x(x + 3) = 180
⇒ x² + 3x - 180 = 0
⇒ x² + 15x - 12x - 180 = 0
⇒ x(x + 15) - 12(x + 15) = 0
⇒ (x + 15) (x - 12) = 0
⇒ x + 15 = 0 or x - 12 = 0
⇒ x = - 15, 12 (As x can't be negative)
⇒ x = 12
Hence, the original duration of the tour is 12 days.
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