a person on tour has rupees 360 for his daily expenses.If he extends his tour by four days,he has cut down his daily expenses by rupees 3 find the original duration of tour
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Amount that the person has = Rs. 360
Let the original no. of tour days = x days
Daily expenses = Rs. 360 / x per day
The person has extended his tour for four days. ( given )
So, daily expenses per day = Rs. 360 / ( x + 4 )
Now, A.TQ.
[ 360 ( x + 4 ) – 360x ] / [ x ( x + 4 ) ] = 3
( 360x + 1440 – 360x ) / ( x² + 4x ) = 3
1440 / ( x² + 4x ) = 3
1440 = 3 ( x² + 4x )
3x² + 12x – 1440 = 0
x² + 4x – 480 = 0
x² – 20x + 24x – 480 = 0
x ( x – 20 ) + 24 ( x – 20 ) = 0
( x – 20 ) ( x + 24 ) = 0
( x – 20 ) = 0 or ( x + 24 ) = 0
x = 20 or x = – 24
Thus, amount can't be negative.
Therefore, the original duration of tour is 20 days.
Amount that the person has = Rs. 360
Let the original no. of tour days = x days
Daily expenses = Rs. 360 / x per day
The person has extended his tour for four days. ( given )
So, daily expenses per day = Rs. 360 / ( x + 4 )
Now, A.TQ.
[ 360 ( x + 4 ) – 360x ] / [ x ( x + 4 ) ] = 3
( 360x + 1440 – 360x ) / ( x² + 4x ) = 3
1440 / ( x² + 4x ) = 3
1440 = 3 ( x² + 4x )
3x² + 12x – 1440 = 0
x² + 4x – 480 = 0
x² – 20x + 24x – 480 = 0
x ( x – 20 ) + 24 ( x – 20 ) = 0
( x – 20 ) ( x + 24 ) = 0
( x – 20 ) = 0 or ( x + 24 ) = 0
x = 20 or x = – 24
Thus, amount can't be negative.
Therefore, the original duration of tour is 20 days.
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