Question

A person pedals from his house to his office at a speed of ${y_1}$ km/hr and returns by the same route at a speed of ${y_2}$ km/hr. What is his average speed?​

Answer 1

Answer:

factorise

[tex](y^2+7y+10)÷(y+2)[/tex

Answer 2

Step-by-step explanation:

y2+y1/2

it will be your answer

if correct then inform me