a person preparing a medicine wants to convert 15% alcohol solution into 32% alcohol solution. find how much pure alcohol he should mix in 400ml of 45% of alcohol solution to obtain required solution?
Answers
Answered by
92
Let the required number of pure alcohol be x.
Given that 15% of 400 ml should be added.
= 15/100 * 400
= 60ml.
Pure alcohol = (60 + x) ml.
New volume = (400 + x)ml.
Given Strength = 32%.
Therefore,
(60 + x)/(400 + x) = 32%
60 + x/400 + x = 32/100
100(60 + x) = 32(400 + x)
6000 + 100x = 12800 + 32x
100x - 32x = 12800 - 6000
68x = 6800
x = 100.
Therefore 100 ml of pure alcohol to be added to make it 32%.
Given that 15% of 400 ml should be added.
= 15/100 * 400
= 60ml.
Pure alcohol = (60 + x) ml.
New volume = (400 + x)ml.
Given Strength = 32%.
Therefore,
(60 + x)/(400 + x) = 32%
60 + x/400 + x = 32/100
100(60 + x) = 32(400 + x)
6000 + 100x = 12800 + 32x
100x - 32x = 12800 - 6000
68x = 6800
x = 100.
Therefore 100 ml of pure alcohol to be added to make it 32%.
Answered by
20
Answer:
Given,
➪A person preparing medicine wants to convert 15% alcohol solution into 32% alcohol solution.
and
x=400ml of 15% alcohol so that,
Let,
x=amount of alcohol that mixed in alcohol solution.
➪15%of 400+x=32%of (400+x)
➪15×400100+x=32×(400+x)100
➪60+x=12800+32×100
➪6000+100x=1280+32x=100x-32x=12800-6000
➪68x=6800
➪x=6800 68
➪x=100
So x =100ml
Therefore, we should mix 100 ml of pure alcohol to convert 15% alcoholic solution into 32% of alcoholic into 32%alcohol solution.....
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