a person preparing a medicine wants to convert 15% alcohol solution to32% alchohal solution .find how much pure alchohal should he mix with 400 ml of 15% alchohol solution to obtain it.
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in 400 ml of alcoholic solution, percent of alcohol is 15%
so, volume of alcohol= 15% of 400 ml
=60 ml
now, 15% is 60 ml, so 1% = 60/15= 4 ml
so , 32 % = 32×4 = 128 ml
volume added= 128 - 60 = 68 ml
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let alcohol to be added be x
required conc = 32%
32=60+x/400+x * 100
32/100=60+x/400+x
32(400+x)=100(60+x)
12800+32x=6000+100x
68x=6800
x= 100ml
So 100ml of alcohol should be added.