Question

a person preparing medicine wants to convert 15% alcohol solution into 32% alcohol solution. Find how much pure alcohol should he mix with 400ml of 15% alcohol solution to obtain it.

Answer 1

let the amount of alcohol added be X
To convert the solution 15% into 32%
A/q
15% of 400ml
15/100*400
15*4
60ml
Now,
the amount of alcohol added is
600+X/400+X=32%
100(60+X)=32(400+X)
6000+100X=12800+32x
100x-32x=12800-6000
68x=6800
X=6800/68
X=100ml ans...

Answer 2

Hi mate,

Solution :

=> Volume of alcohol in 400 ml solution

➾ 0.15 × 400 ml

=> Volume of alcohol in 400 ml solution

➾ 60 ml

=> Volume of others liquid

➾ 340 ml

=> Let x ml of alcohol is added to make it 32% strong

=> Then, volume of alcohol

➾ 60+x ml

=> Volume of other liquid

➾ 340 ml

=> Volume of solution

➾ 400 + x ml

➾ 0.32 × (400 + x) = 60 + x

➾ 128 + 0.32x = 60 + x

➾ 0.68x = 68

➾ 68x = 6800

➾ x = 100 ml ...

Answer : 100 ml pure alcohol must be added to 400ml of a 15% solution to make it's strength 32%

i hope it helps you