Question

A person pulls a box on a horizontal surface by applying a force of 5 N at an angle of 60° with the horizontal. The work done by this force in displacing the box through 2 m is​

Answer 1

Answer:

Here is your answer dear!

Answer 2

Solution:-

Work Done=F(Force)×S(Displacement)

Work Done=5×2×cos 60°

[Value of cos 60° is $\sf \dfrac{1}{2}$]

Work Done=5×2×$\sf \dfrac{1}{2}$

Therefore Work Done=10×$\sf \dfrac{1}{2}$

Therefore Work Done=5 Joule