Question

A person pulls horizontally on blocK WITH A 5N force, at an angle of 60 with the horizontal surface. The work done in displacing block is 200 J, the displacement is
a) 80km
b)80m
c)50m
d)none of the above



it's urgent help me

Answer 1

Answer :

• Displacement of the body, s = 80 m.

Explanation :

Given :

• Force applied to pull the block, F = 5 N
• Angle on which the force is applied, θ = 60°
• Work done by the person, W = 200 J

To find :

• Displacement of the block, s = ?

Knowledge required :

Work done by the body is the product of the body magnitude and displacement of the body along the given angle.

So the formula for work done will be,

⠀⠀⠀⠀⠀⠀⠀⠀⠀W = F s cosθ⠀

Where,

• W = Work done by the body.
• F = Force exerted by the body.
• s = Displacement of the body.
• θ = Angle on which the force is applied.

Solution :

By using the formula for work done by the body and substituting the values in it, we get :

⠀⠀=> W = F s cosθ

⠀⠀=> 200 = 5 × s × cos60°

⠀⠀=> 200 = 5 × s × ½ [cos60° = ½]

⠀⠀=> 200 × 2 = 5s

⠀⠀=> 400 = 5s

⠀⠀=> 400/5 = s

⠀⠀=> 80 = s

⠀⠀⠀⠀∴ Displacement (s) = 80 m

Hence the displacement of the body is 80 m.

Answer 2

Answer:

Answer:

$\huge\boxed{\fcolorbox{purple} {black}{\color{yellow}{Answer—}}}$

80 m

SOLUTION :

GIVEN :

Force applied to the block=5 N

Angle on which force is applied = 60°

Work done by the force = 200 J

TO FIND :

Displacement of the block.

$\large\overline{\underline{\pink{IMPORTANT \: \: TO \: \: KNOW</p><p>}}}$

Work done by the body is equal to the product of the force applied and displacement of the body along the given angle.

Hence formula for work is —

$\green{\boxed{\boxed{\boxed{W = FS \cos( \alpha ) }}}}$

Where —

W is work done

F is force applied

S is displacement

$\alpha$ is angle on which force is applied

$\large \overline{\underline{\pink{SOLUTION}}}$

By applying the formula and substituting the values we get

$\implies W = FS \cos( \alpha )$

$\implies 200 = 5 \times S \times \cos( 60 )$

$\implies 200 = 5 \times S \times \frac{1}{2} (since \: \cos(60) = \frac{1}{2} )$

$\implies 40 = \frac{S}{2}$

$\red{\implies 80 \: m \: = S}$

$\boxed{\boxed{Displacement \: Of \: the \: body = 80 \: m</p><p>}}$

_________________

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