Question

A person ran with a speed of 6 m/s and jumped onto a skateboard. What is the speed with which he will ride on theskate board?​

Answer 1

Answer:

First, remember the conservation of energy.

We can define the kinetic energy as:

K = (1/2)*m*v^2

where m is the mass, and v is the velocity. The velocity of the person is 6m/s, and the mass is unknown.

Now, when the person rides the skateboard, this kinetic energy must remain constant, if M is the mass of the skateboard, the speed after the person rides ir will be:

K' = (1/2)*(m + M)*v*^2

Where v' is the new velocity. In this case, we can suppose that the skateboard has really small mass compared with the

person.

M<<m

then:

(m + M) = m

then:

K' = (1/2)*m*v^2 = K = (1/2)*m*v^2

from that equation, we can conclude that:

V' =V

Then if the velocity before riding the skateboard was 6m/s, then after would be also 6m/s.

Explanation:

Hope It helps you