Math, asked by SwaritRao, 8 hours ago

A person reared cows and buffaloes. The number of buffaloes was 7 more than one third of the number of cows. What was the total number of animals if the number of buffaloes was 21​

Answers

Answered by varshini0785
0

Answer:

Step-by-step explanation:

let the total be x

buffaloes=21

cows=x/3+7

x/3+7=21

x=14×3

x=42

cows=42/3+7

cows=21

Total=42

I think this is the answer

Answered by ommandkulkar46
1

Step-by-step explanation:

sorry but I will not help you in your textbook ans but answer will be 63 and cows will be 56

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