A person reared cows and buffaloes. The number of buffaloes was 7 more than one third of the number of cows. What was the total number of animals if the number of buffaloes was 21
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Answer:
Step-by-step explanation:
let the total be x
buffaloes=21
cows=x/3+7
x/3+7=21
x=14×3
x=42
cows=42/3+7
cows=21
Total=42
I think this is the answer
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1
Step-by-step explanation:
sorry but I will not help you in your textbook ans but answer will be 63 and cows will be 56
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