A person returns by car at a speed of 72km/h from city A to city B and returns from B to A at a speed of 40km/h. Find out his average speed?
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Answer:
51.43 Km/h
Step-by-step explanation:
According to the question
A----->B with a speed of 72km/h
B----->A with a speed of 40km/h
As we can see that the Distance is same
The average speed will be (2xs1xs2)/(s1+s2)
(2 x 72 x 40)/(72+40)
5760/112
51.43 km/h
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