Question

A person running down the hallway at a velocity of 4.2 m/s comes to a stop in a time of 1.8 seconds to avoid hitting the wall. What was the acceleration of the person?
1.) -7.6 m/s/s
2.) -2.3 m/s/s 3.) 2.3 m/s/s
4.) 7.6 m/s/s

Answer 1

Answer:

We know that

v=0

u=4.2

t=1.8

By using

v=u+at

0=4.2+1.8a

-4.2/1.8=a

a=2.3m/s² ANS