Question

a person runs with constant velocity v through a forest of coconut tree a coconut start to fall from height h when the person is directly below it how far behind the person will the coconut land
1. √2hv^2/g
2. √hv^2/2g
3. gh^2/2v^2
4. 2gh^2/v^2​

Answer 1

Answer:

1

Explanation:

time taken for the coconut to fall in the ground t=£(2h/g) (consider £ as rootover)

in that time distance travelled by the person is vt

Answer 2

Answer:1. √2hv^2/g

Explanation:

the time taken by the coconut to fall is given by

s = 1/2gt² , and s = h

so, t = √(2h/g) ....

now in this time t , the total distance travelled by the jogger is

d = v × t = v√2h/g = √2hv²/g .

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