Question

A person's age is 125% of what it was one decade ago, but 83(1/3)% of what it will be after one decade. what is his current age? [1 decade = 10 years]

Answer 1

Let the current age = x year

One decade ago:

The age = x - 10 years

x = 125/100(x - 10)

x = 1.25x - 12.5

x - 1.25x = -12.5

-0.25x = - 12.5

x = 50 years


One decade to come:

The age = x + 10

x = 83(1/3)/100(x + 10)

x = 5/6x + 8(1/3)

x - 5/6x = 8(1/3)

1/6 x = 8(1/3)

x = 50

The two solutions show that he is 50 years old now.

Answer 2

Answer:

Step-by-step explanation:

Let the current age = x year

One decade ago:

The age = x - 10 years

x = 125/100(x - 10)

x = 1.25x - 12.5

x - 1.25x = -12.5

-0.25x = - 12.5

x = 50 years

One decade to come:

The age = x + 10

x = 83(1/3)/100(x + 10)

x = 5/6x + 8(1/3)

x - 5/6x = 8(1/3)

1/6 x = 8(1/3)

x = 50

The two solutions show that he is 50 years old now.