Question

A person saved ₹16,500 in all during 10years . After the first year, every year he saved ₹100 more than what he had saved the previous year. Find his savings of the first year.

Answer 1

In the 10 year he saves Rs 16500

Think of this as an AP.

d=Rs 100

Given d=100

Sn= 16500

n=10

We have to find a

Sn=n/2*[2a+(n-1)d]

16500=10/2*[2a+9*100]

16500=5*[2a+900]

3300=2a+900

2a=2400

a=2400/2

=1200

So his saving for the first year was 1200.

Hope it helps.