Question

a person saved every year half as much as he saved previous year if he totally saved rupees 19375 in 5 years how much did he saved the first year​

Answer 1

Answer:

let the 1st yr savings =x

2nd yr =0.5x

3rd yr = 0.25x

4th yr = 0.125x

5th yr = 0.0625x

x+0.5x+0.25x+0.125x+0.0625x=19375

1.9375x=19375

x=10000

Answer 2

He saved 10000 rupees first year.

Step-by-step explanation:

Consider the provided information.

a person saved every year half as much as he saved previous year if he totally saved rupees 19375 in 5 years.

$r=\frac{1}{2}, n=5\ and\ s_n=19375$ we need to find the value of a.

Use the formula for sum: $S_n=a(\frac{1-r^n}{1-r})$

$19375=a(\dfrac{1-(\frac{1}{2})^5}{1-\frac{1}{2}})$

$19375=a(\dfrac{1-\frac{1}{32}}{\frac{1}{2}})$

$19375=a(\dfrac{31}{16})$

$a=\frac{19375\times16}{31}\\\\a=10000$

Hence, he saved 10000 rupees first year.

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