Question

a person saves 5 minutes by increasing speed by 20 percentage what is the time taken to cover the distance at his usual speed​

Answer 1

solution is in the above image.










































don't forget to follow

Answer 2

B

Solution

Let speed is ‘x’

‘x’ is increased by 20%20%

New speed =x+20%=x+20%  of x

=x+20x100=6x5=x+20x100=6x5

The new speed is 6x56x5  of the usual speed

New time taken =5x6=5x6  of the usual time

So,

(usual time−5x6 of the usual time)=5mints(usual time−5x6 of the usual time)=5mints

x6x6  of usual time =5=5

∴∴  usual time =30=30 mints

Chapter

02_Arithmetic