Question

A person sells a table at a profit of 10%. If he had bought the table at 5% less cost and sold for Rs. 80 more, he would have gained 20%. The cost price of table is.​

Answer 1

Answer:

Rs.2000

Step-by-step explanation:

Let the CP of Table = 100x

Initial SP = 100x + 10% of 100x = 100x + 10x = 110x

If the person brought table at 5% discount

CP = 95x

SP = 95x + 20% of 95x = 95x + 17x =114x

SP - SP = 80

⇒ 114x - 110x = 80

⇒ 4x = 80

⇒ x = 20

Cost of table = 100 × 20 = Rs. 2000

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Answer 2

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$Let \: \: the \: \: CP1 \: \: of \: \: Table = \: 100x$

$Initial \: SP1 = 100x \: + \: 10%$

$\: of 100x = 100x + 10x = 110x$

Now, If He brought table at 5% discount.

Therefore,

$CP2 = 95x$

Now ,

$SP2 = 95x + 20%$$of \: 95x = 95x + 17x =114x$

According to question

$SP2 - SP1 = 80$

$⇒ 114x - 110x = 80$

$⇒ 4x = 80$

$⇒ x = 20$

Initial Cost of table =

• 100 × 20
• Rs. 2000

_________________

Hope it's Helpful :)