Question

A person sets out to cross a forest. On the first day, he completes 1/10th of the total distance. On the second day,he covers 2/3rd of the distance already travelled on the first day. He continues in this manner, alternating the days inwhich he travels 1/10th of the distance still to be covered on one day, with days on which he travels 2/3rd of the totaldistance already covered on the next day. At the end of the seventh day, he finds 45/2 km more will see the end ofhis journey. What is the total distance that he has to cover?​

Answer 1

Answer :-

Let total distance = 90x km .

so,

→ first day he cover = (1/10) of 90x = 9x km

and,

→ second day he cover = (2/3) of 9x = 6x km .

so,

→ In 2 days he cover = 15x km

→ In 6 days he cover = 15 * 3 = 45x km .

now,

→ On 7th day he cover = 9x km

then,

→ distance covered in 7 day = 45x + 9x = 54km .

A/q,

→ Distance left to be uncovered after 7 days = (45/2) km .

→ 90x - 54x = 45/2

→ 36x = 45/2

→ x = (45/2) * (1/36)

→ 90x = (45/2) * (1/36) * 90 = 56.25 km (Ans.)

Hence, the total distance that he has to cover is 56.25 km .

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