Question

.A person shooting at a target from a distance of 450 metres finds that the sound of the bullet hitting the target comes 1/2 seconds after he fired.A person equidistant from the target and shooting point hears the bullet hit 3 seconds after he heard the gun.The speed of sound is


290

300

370

450​

Answer 1

Answer:

3000 m/sec

Step-by-step explanation:

Average speed = Total distanceTotal time

S = 450m/112s

=300 m/s

Answer 2

Answer:

speed of sound = 300 m/s

Step-by-step explanation:

Question is wrong..(the sound of the bullet hitting the target comes after he fired must be higher than the other person hearing it in 3 sec gap)

If consider that the sound of the bullet hitting the target comes 4 1/2 seconds after he fired

$bullet \: travelling \: time \: + time \:taken \: for \: sound \: to \: reach \: back \: = \: 4.5 \: sec \\ time \: = \frac{distance}{speed}$

let the speed of bullet be a

let the speed of sound be b

$\frac{450}{a} + \frac{450}{b} = 4.5 \:.........(1)$

person hears firing sound and sound of bullet hitting the target at 3 s interval

$\frac{450}{a} + \frac{x}{b} - \frac{x}{b} = 3 \\ a = 150 \: \frac{m}{s}$

Substitute a = 150 in equation (1)

$3 + \frac{450}{b} = 4.5 \\ b = 300 \: \frac{m}{s}$

Speed of sound = 300 m/s

(or)

since the other person is same distance from both target and shooting spot the sound heard by him at time interval 3 sec is the actual bullet traveling time to hit a target.

Remaining time = 4.5 - 3 = 1.5

Speed of sound = 450/1.5 = 300 m/s