Physics, asked by KingNipunDK, 11 months ago

A person sitting on the top of a tall building is dropping ball at regular intervals of one second.Find the positions of the 3rd 4th and 5th ball when the ball is being dropped.

Explain with full explanation ​

Answers

Answered by amitnrw
75

Answer:

the positions of the 3rd 4th and 5th ball are 45 m , 20 m & 5 m below the top of tower when 6th ball is being dropped.

Explanation:

A person sitting on the top of a tall building is dropping ball at regular intervals of one second.Find the positions of the 3rd 4th and 5th ball when the 6th ball is being dropped.

when the 6th ball is being dropped.

5th ball has travelled for 1 sec

4th Ball for 2 sec

3rd Ball for 3 sec

S = ut  +(1/2)at²

u = 0 dropped  

a = g = 10 m/s²

t = 1 , 2 , 3

Distance Covered in 1 Sec =  (1/2)10*1² = 5 m

Distance Covered in 2 Sec =  (1/2)10*2² = 20 m

Distance Covered in 3 Sec =  (1/2)10*3² = 45 m

the positions of the 3rd 4th and 5th ball are 45 m , 20 m & 5 m below the top of tower when 6th ball is being dropped.

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