Math, asked by vichusurendran567, 1 day ago

A person spends 30% of his monthly income on rent, ‘X’ % on sports, ‘Y’% on transport and rest is saved by him which is Rs 4800. If his monthly income is Rs 12000 and value of ‘Y’ is one-third of the value of ‘X’ then how much amount does he spend on transport?​

Answers

Answered by nayanborgohain17
1

Answer:

Rs900

Step-by-step explanation:

Given,

Rent = 30% of 12000

x% = x%

y% = 1/3x

Remaining = 4800

To find,

Money spent on transport (y%)

Procedure,

money \: spent \: on \: rent = 30\% \: of \: 12000 \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  \frac{30}{100}  \times 12000 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    =  \frac{30 \times 12000}{100}   \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  \frac{360000}{100}   \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  3600

money \: that \: remains \: from \: 12000 = 4800

 \therefore \: money  \: left \: for \:  x \: and \: y =   1 2000 - (3600 + 4800)  \\ = 12000 - 8400 \\  = 3600

So, we have 3600 that is to be distributed between x and y. And ultimately y will be the answer.

Now,

Let x = 3x

y = x

3x + x = 3600

4x = 3600

x = \frac{3600 }{4}

x = 900

Now,

3x = 900 \times 3 \\  = 2700

x   \:  \:  \:  = 900 \times 1 \\  = 900

Therefore,

X = 3600

Y = 900.

Our answer is y.

Therefore, total money spent on transport is Rs900.

Hope it helps you

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