Question

A person spent ₹546 in buying pens and pencils if cost of each pen is ₹ 7 and each pencil is ₹3 and if the total number of things bought was 108, how many of each type did he buy?

Answer 1

Let
No. Of pens=x
No. Of pencils=y
Equation 1:
7x+3y=564
Equation2:
x+y=108
After elimination method you will get x=60
Y=48


Hope this helps you!!

Answer 2

He bought 48 pencils and 60 pens

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Given :

Cost of each pen = Rs 7

Cost of each pencil = Rs 3

Total number of things bought = 108

Total cost spent by the person = 564

To Find :

Total no. of pen and pencils bought by the person.

Solution :

Let the no. of pens be x and no. of pencils be y.

According to the question,

⟹ x + y = 108 [ Equation 1 ]

⟹ 7x + 3y = 564 [ Equation 2 ]

⟹ x = 108 - y [ Equation 3 ]

_____________________

Now,

• Substituting the value of x in Equation 2,

⟹ 7x + 3y = 564

⟹ 7(108 - y) + 3y = 564

⟹ 756 - 7y + 3y = 564

⟹ - 4y = 564 - 756

⟹ 4y = 192

⟹ y = 192/4

⟹ y = 48

Same here,

• Substituting the value of y in Equation 3,

⟹ x = 108 - y

⟹ x = 108 - 48

⟹ x = 60

Therefore,

• No. of pens = 60
• No. of pencils = 48