A person spent ₹546 in buying pens and pencils if cost of each pen is ₹ 7 and each pencil is ₹3 and if the total number of things bought was 108, how many of each type did he buy?
Answers
Answered by
2
Let
No. Of pens=x
No. Of pencils=y
Equation 1:
7x+3y=564
Equation2:
x+y=108
After elimination method you will get x=60
Y=48
Hope this helps you!!
Answered by
6
He bought 48 pencils and 60 pens
_____________________
Given :
Cost of each pen = Rs 7
Cost of each pencil = Rs 3
Total number of things bought = 108
Total cost spent by the person = 564
To Find :
Total no. of pen and pencils bought by the person.
Solution :
Let the no. of pens be x and no. of pencils be y.
According to the question,
⟹ x + y = 108 [ Equation 1 ]
⟹ 7x + 3y = 564 [ Equation 2 ]
⟹ x = 108 - y [ Equation 3 ]
_____________________
Now,
- Substituting the value of x in Equation 2,
⟹ 7x + 3y = 564
⟹ 7(108 - y) + 3y = 564
⟹ 756 - 7y + 3y = 564
⟹ - 4y = 564 - 756
⟹ 4y = 192
⟹ y = 192/4
⟹ y = 48
Same here,
- Substituting the value of y in Equation 3,
⟹ x = 108 - y
⟹ x = 108 - 48
⟹ x = 60
Therefore,
- No. of pens = 60
- No. of pencils = 48
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