A person spent 564 in buying pens and pencils if cost of each pen is 7 and each pencil is 3 and if the total number of things bought was 108, how many of each type did he buy?
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Step-by-step explanation:
⇒ Let the number of pens be x.
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=564
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=564
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=564
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−324
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−3244x=240
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−3244x=240∴ x=
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−3244x=240∴ x= 4
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−3244x=240∴ x= 4240
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−3244x=240∴ x= 4240
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−3244x=240∴ x= 4240 =60
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−3244x=240∴ x= 4240 =60⇒ Number of pencils =108−60=48
⇒ Let the number of pens be x.⇒ Then, number of pencils =108−x⇒ Cost of pens =7x⇒ Cost of pencils =3(108−x)According to the question,7x+3(108−x)=5647x+324−3x=5644x+324=5644x=564−3244x=240∴ x= 4240 =60⇒ Number of pencils =108−60=48∴ The number of pens bought are 60 and pencil bought are 48.
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