A person spent 564$ in buying pens and pencils if each pen cost is 7$and each pencil is 3$ and if the total number of things bought was 108,how many of each type did he buy?
Answers
Answered by
24
Hi there,
Pen cost rs7
Pencil cost rs3
Total number of things = 108
The person spent rs 564
Make pens = x
Make pencils = y
x + y = 108......(1)
7x + 3y = 564.....(2)
Multiply (1) by 7
7x + 7y = 756.....910
7x + 3y = 564
Subtract (2) from (1)
....4y = 192
....y = 48
Substitute y = 48
into Equation (1)
x + y = 108
x + 48 = 108
x = 108 = 48
x = 60.
Therefore:
48 pencils were bought
60 pens were bought.
Hope this helps:-)
Pen cost rs7
Pencil cost rs3
Total number of things = 108
The person spent rs 564
Make pens = x
Make pencils = y
x + y = 108......(1)
7x + 3y = 564.....(2)
Multiply (1) by 7
7x + 7y = 756.....910
7x + 3y = 564
Subtract (2) from (1)
....4y = 192
....y = 48
Substitute y = 48
into Equation (1)
x + y = 108
x + 48 = 108
x = 108 = 48
x = 60.
Therefore:
48 pencils were bought
60 pens were bought.
Hope this helps:-)
Answered by
3
pen cost 7$ = 60
pencil cost3$ =48
to total is 108 and spent amount is 564$
I hope it help you
pencil cost3$ =48
to total is 108 and spent amount is 564$
I hope it help you
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