A person spent rupees 564 in buying pens and pencils if cost of own is 7 and each pencil is 3 and if the total no of things bought was 108 how many of each type did he buy?
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Answered by
26
let no of pens be x,
pencils be y
so total no of things bought 108
therefore x+y=108
cost a pen = 7
cost of pencil= 3
total pendure = 564
so 7x+3y=564
therefor the solving the equation
7x+3y=564
3x+3y=324 ( multiple 3 to x+y=108)
you get x = 60
so the no of pens bought are 60 and pencil bought are 48
pencils be y
so total no of things bought 108
therefore x+y=108
cost a pen = 7
cost of pencil= 3
total pendure = 564
so 7x+3y=564
therefor the solving the equation
7x+3y=564
3x+3y=324 ( multiple 3 to x+y=108)
you get x = 60
so the no of pens bought are 60 and pencil bought are 48
Answered by
8
AnswerL=59 B =29•5
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