A person spent rupees 564 in buying pens and pencils , pens cost is 7 rupees and each pencil cost is 3 rupees and if the total no of things bought was 108, how many each type did he buy?
please give me full answer..........
anuvelpula1:
answer is 60,48
Answers
Answered by
607
Let the number of pens be x.
number of pencils=108-x
cost of pens=7x
cost of pencils=3(108-x)
7x+3(108-x)=564
7x+324-3x=564
4x+324=564
4x=564-324
4x=240x=240/4
x=60
Number of pens=60
Number of pencils=108-60=48
number of pencils=108-x
cost of pens=7x
cost of pencils=3(108-x)
7x+3(108-x)=564
7x+324-3x=564
4x+324=564
4x=564-324
4x=240x=240/4
x=60
Number of pens=60
Number of pencils=108-60=48
Answered by
99
Answer:
Step-by-step explanation:
Pen=7rupees
Pencil=3rupees
Total items=108
Total Pens can be written as 7(x)
Total pencils can be written as 3(108-x)
7(x)+3(108-x)=564
7x+324-3x=564
4x=564-324
4x=240
Hence,x=60(total pens)
(108-x)=(108-60)
Total no.of pencils =48.
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