A person stand straight in front of a convex mirror at a distance of 30m away from it .He sees his erect image whose height is 1÷6th real height .Find focal length of the convex mirror
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Height of image/height of object=-v/u
1/6=-v/30
V=-5
As it is a convex mirror ,due to sign convention v=5 &u=-30
1/v+1/u=1/f
1/5+1/-30=1/f
1/f=30-5/150
f=150/25
f=6m
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