A person standing at the crossing at two straight paths represented by the equations 2x-3y-4= 0 and 3x-4y-5 = 0, wants to reach a path represented by 6x-7y+8 = 0 in least time. Find the equations of path he should follow
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Answered by
2
firstly intersection of two lines gives position of person = (-1,-2)
now he wants to reach to line 6x - 7y +8=0
that implies he has to walk through perpendicular line cause perpendicular dis is least
so eq of perpendicular i s= y-(-2)/x-(-1) = 7/6
⇒ 7x - 6y = 5
hope my ans is correct
now he wants to reach to line 6x - 7y +8=0
that implies he has to walk through perpendicular line cause perpendicular dis is least
so eq of perpendicular i s= y-(-2)/x-(-1) = 7/6
⇒ 7x - 6y = 5
hope my ans is correct
Answered by
21
7x-6y = 5
Hope this will help you.
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