CBSE BOARD X, asked by mohammedmohammedusma, 9 months ago

A person standing between the two vertical cliffs produces a sound. Two successive (3) echoes are heard at 6s and 8s. Calculate the distance between the cliffs. (speed of sound in air =330 m/s)

Answers

Answered by papiyaghosh1976kgp
0

Answer:

Distance traveled by the sound from the 1

st

cliff is calculated with the formula:

Distance traveled = velocity of sound × time taken

That is, 320×4 =1280 m.

This is twice the minimum distance between a source of sound (man) and the reflector (1

st

cliff) as it is reflected sound.

Distance traveled by the sound from the 2

nd

cliff is calculated with the formula:

Distance traveled = velocity of sound × time taken

That is, 320×6=1920 m.

This is twice the minimum distance between a source of sound (man) and the reflector (2

nd

cliff) as it is reflected sound.

Hence, the distance between the 2 cliffs is given as:

2

1280

+

2

1920

=640+960=1600 m

Answered by peachiYadav
0

Answer:

Distance traveled by the sound from the 1

st

cliff is calculated with the formula:

Distance traveled = velocity of sound × time taken

That is, 320×4 =1280 m.

This is twice the minimum distance between a source of sound (man) and the reflector (1

st

cliff) as it is reflected sound.

Distance traveled by the sound from the 2

nd

cliff is calculated with the formula:

Distance traveled = velocity of sound × time taken

That is, 320×6=1920 m.

This is twice the minimum distance between a source of sound (man) and the reflector (2

nd

cliff) as it is reflected sound.

Hence, the distance between the 2 cliffs is given as:

2

1280

+

2

1920

=640+960=1600 m

Similar questions