A person standing between the two vertical cliffs produces a sound. Two successive (3) echoes are heard at 6s and 8s. Calculate the distance between the cliffs. (speed of sound in air =330 m/s)
Answers
Answer:
Distance traveled by the sound from the 1
st
cliff is calculated with the formula:
Distance traveled = velocity of sound × time taken
That is, 320×4 =1280 m.
This is twice the minimum distance between a source of sound (man) and the reflector (1
st
cliff) as it is reflected sound.
Distance traveled by the sound from the 2
nd
cliff is calculated with the formula:
Distance traveled = velocity of sound × time taken
That is, 320×6=1920 m.
This is twice the minimum distance between a source of sound (man) and the reflector (2
nd
cliff) as it is reflected sound.
Hence, the distance between the 2 cliffs is given as:
2
1280
+
2
1920
=640+960=1600 m
Answer:
Distance traveled by the sound from the 1
st
cliff is calculated with the formula:
Distance traveled = velocity of sound × time taken
That is, 320×4 =1280 m.
This is twice the minimum distance between a source of sound (man) and the reflector (1
st
cliff) as it is reflected sound.
Distance traveled by the sound from the 2
nd
cliff is calculated with the formula:
Distance traveled = velocity of sound × time taken
That is, 320×6=1920 m.
This is twice the minimum distance between a source of sound (man) and the reflector (2
nd
cliff) as it is reflected sound.
Hence, the distance between the 2 cliffs is given as:
2
1280
+
2
1920
=640+960=1600 m